TuDelField
| Format: TuDelField (object.field) |
Purpose: Deletes an object field. The object.field parameter must denote an object field, which means that it must be an expression of the form t.name or t[expr] where t must be an object. The resulting object does not contain the specified field any more. The field index of all subsequent fields is decremented by one.
Return Values: The TuDelField() function does not return a useful value.
Example:
| resulting output: | |
<? splitstring("H.E.I", ".")> | ([0]="H", [1]="E", [2]="I") |
<let s=splitstring("H.E.I", "."); TuDelField(s[1]); ? s> | ([0]="H", [1]="I") |
See Also: TuAppField(), TuAssField(), TuAssign(), TuFieldSort(), TuInsField(), TuMerge(), TuName(), TuProject(), TuSlice().
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